try catch finally

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java

Which of the following parts of the code will not cause the compilation errors?

try catch finally

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What will be printed out as the result of the following code execution? public class Exceptions { public static void main(String[] args) { try { throw new UnsupportedOperationException(); } catch(Throwable t) { System.out.print("1"); } catch(Exception e) { System.out.print("2"); } catch(UnsupportedOperationException uoe) { System.out.print("3"); } } }

try catch finally

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What will be printed as the result of the following program execution? public class C { public static void main(String[] args) { try { foo(); System.out.print("A "); } catch (Exception e) { System.out.print("B "); } finally { System.out.print("C "); } } private static void foo() throws Exception { try { System.out.print("A1 "); throw new Exception(); } catch (Exception e) { System.out.print("B1 "); throw new Exception(); } finally { System.out.print("C1 "); } } }

try catch finally

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What is the output of following code: String s = "BIRD"; try { String x = "DOG"; throw new Exception(); } catch (Exception e) { s = "CAT"; } finally { s = "GOAT"; x = "FROG"; } System.out.println(s);

try catch finally

java

What will be the output of the following code? class Test { private int i; public void setI(int i) { this.i = i; } public int getI() { return i; } } public class Main { private Test t; public int getSomeInteger() { try { return t.getI(); } finally { return 0; } } public static void main(String[] args) throws Exception { Main m = new Main(); System.out.println(m.getSomeInteger()); } }

try catch finally

java

Can this method ever throw exception? public static int getTest() { try { // arbitrary code here } finally { return 1; } }

try catch finally

java

What will print the following code: public class ExceptionHandling { public static void main(String[] args) { double dbl = 1.0; try { dbl = dbl / 0; System.out.println("unreachable"); } catch (ArithmeticException e) { System.out.println("reachable"); } finally { System.out.println("reachable"); } System.out.println("unreachable"); } }

try catch finally

java

Is it possible to modify the following programm by inserting some code into the marked space to make it comply to the following conditions: - it finishes (no infinite loop) - it does not print "Finally"? class Clazz { public static void main(String[] args) { for (int i = 0; i < 2; i++) { try { System.out.println("Try"); // INSERT CODE HERE } finally { System.out.println("Finally"); } } } }

try catch finally

java

public class ExceptionTest { public static void errorHandling() { System.out.println("Error"); throw new IllegalAccessException(); } public static void main(String[] args) { try { errorHandling(); } catch (IllegalAccessException e) { System.out.println("Main error"); } } } What is the result of executing?

try catch finally