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What is the result of the compilation and execution of the following code with the parameters a = 0, b = 3? public void divide(int a, int b) { try { int c = a / b; } catch (Exception e) { System.out.print("Exception "); } finally { System.out.println("Finally"); } }

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What will be the result of the compilation and execution of the following code? 01. class A { 02. public void process() { System.out.print("A,"); } 03. } 04. public class B extends A { 05. public void process() throws IOException { 06. super.process(); 07. System.out.print("B,"); 08. throw new IOException(); 09. } 10. 11. public static void main(String[] args) { 12. try { new B().process(); } 13. catch (IOException e) { System.out.println("Exception"); } 14. } 15. }

try catch finally

java

What will happen when you try to compile and run the following code? It is assumed that the outstream file is already created. import java.io.*; public class Main { public static void main(String[] args) { try { FileInputStream fis = new FileInputStream("outstream"); InputStreamReader isr = new InputStreamReader(fis); BufferedReader br = new BufferedReader(isr); try { do { String str = br.readLine(); System.out.println(str); } while (str != null); } finally { fis.close(); isr.close(); br.close(); } } catch(IOException e){ e.printStackTrace(); } } }

try catch finally

java

What will be printed to standard output stream if a tryThis() method throws an IOException? try { tryThis(); return; } catch (IOException x1) { System.out.println("exception 1"); return; } catch (Exception x2) { System.out.println("exception 2"); return; } finally { System.out.println("finally"); }

try catch finally

java

Select the only correct program output when it is run by a "java Test 1 two 3" command. public class Test { static public void main(String[] args) { try { int k = Integer.parseInt(args[1]); System.out.println(args[k]); } catch (Exception e) { System.out.println(e); } } }

try catch finally

java

What is the result of the following code execution? public class Main { public static void main(String... args) { System.out.println("" + new Main().summ(3, 3)); } public int summ(int a, int b) { try { return a + b; } finally { if (a == b) return 0; } } }

try catch finally

java

try { int a = 0; int b = 42/a; System.out.print("A"); } catch (Exception e) { System.out.print("C"); } catch (ArithmeticException e) { System.out.print("B"); }

try catch finally

java

What will the following code fragment type: try { int i = 5; } catch (Exception e) { System.out.print("catch"); } finally { System.out.print("finally"); }

try catch finally

java

What will be the result of displaying this code? public class Main { static int method() { for (int i = 0; i < 5; i++) { System.out.println("i = " + i); try { if (i == 1) { throw new Exception(); } } catch (Exception e) { System.out.println("Exception!"); return i; } finally { System.out.println("Finally block"); } } return -1; } public static void main(String[] args) { System.out.println("method() returned " + method()); } }

try catch finally

java

What is the result of executing this code: try { int i = new Integer(10); System.out.println(i); } catch(Exception e) { System.out.println("opsss... error"); }

try catch finally